The Sequences - 08/04/2013

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The Sequences - 08/04/2013

Postby showmyiq » Mon Apr 08, 2013 8:09 am

The Sequences

What number comes next in this sequence?
Why?

1, 1, 1, 1, 2, 1, 1, 3, 3, 1, 1, 4, ?
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Re: The Sequences - 08/04/2013

Postby nagatr0n » Mon Apr 08, 2013 9:12 am

There is repeating pattern in the sequence. Uneven number written twice (1,1), followed by (1,1), then even number typed once (2), followed by (1,1), etc. Next number should be 1.
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Re: The Sequences - 08/04/2013

Postby showmyiq » Mon Apr 08, 2013 9:23 am

I agree with your logic.

The pattern you have found is correct and it’s really a possible solution. You have implemented 3 rules:

1)After each iteration add (1,1)
2) If the number in the iteration is odd – add it twice
3)If the number in the iteration is even – add it once

Following this rules the next numbers should be (1,1).

But can you find such algorithm with using only 1 rule?

This sequence is hiding deep logic and I am sure you can extract it!

( you are almost there – just find the pattern in the pattern you have already found).
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Re: The Sequences - 08/04/2013

Postby showmyiq » Fri Apr 12, 2013 7:12 am

The puzzle is solved by Sergey Sokolov via facebook. I will add our conversation there:

Sergey Sokolov 6. *11

Show My IQ Can you please explain how did you reach that answer? ( I am not able to understand 6 or 11 is your answer, or you have found logic for both?)

Sergey Sokolov 11^n. 1, 11, 121, 1331, 14641

Show My IQ LoL, that's why I asked you about how did you reach the answer, because I didn't created the puzzle using powers of 11th - but still your logic and answer is absolutely correct. I have created the puzzle using Pascal Triangles - https://en.wikipedia.org/wiki/Pascal's_triangle

Show My IQ But what a coincidence! I am amazed! The very next power of 11 though, will not be equal to the next Pascal row - 161051

Sergey Sokolov lol I also noticed that a power of 11 starting from 5th is no longer a palindrome.
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